Question

For what value of k, x = - 1/2satisfies kx^2 - 3x - k=0?​

Answer 1

Answer:

Step-by-step explanation:

k*-1/2^2-3*-1/2-k=0

k/4+3/2-k=0

k-4/4=-3/2

-3k/4=-3/2

k=4/-3*-3/2

k=2

Answer 2

Answer:

the value of k is 2

Step-by-step explanation:

$given \: x = \frac{ - 1}{2} \\ \: now \: k {x}^{2} - 3x - k = 0 \\ = >k { ( - \frac{1}{2}) }^{2} - 3( - \frac{ 1}{2} ) - k = 0 \\ = > k \times \frac{1}{4} + \frac{3}{2} - k = 0 \\ = > \frac{k}{4} + \frac{3}{2} - k = 0 \\ = > \frac{k + 6 - 4k}{4} = 0 \\ = > k - 4k + 6 = 0 \times 4 \\ = > - 3k + 6 = 0 \\ = > - 3k = - 6 \\ = > k = \frac{ - 6}{ - 3} = 2$

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