Question

For what value of k, x=1 and y=0, is a solution of..
(k+2/k-1)x-(3k-2/k+2)y-3=0.​

Answer 1

Answer:

k = 1/2

Step-by-step explanation:

Given,

    x=1 and y=0, is a solution of the equation (k+2/k-1)x-(3k-2/k+2)y-3=0.​

So, substitute the values of x and y in the equation.

(k+2/k-1)(1)-(3k-2/k+2)(0)-3=0.​

⇒k+2/k-1 - 3 = 0

⇒k+2/k-1 = 3

Cross multiplying,

⇒k+2 = 3k - 3

⇒k - 3k = -3 + 2

⇒ -2k = -1

⇒ k = 1/2

Answer 2

Given,

   x=1 and y=0, is a solution of the equation (k+2/k-1)x-(3k-2/k+2)y-3=0.​

So, substitute the values of x and y in the equation.

(k+2/k-1)(1)-(3k-2/k+2)(0)-3=0.​

⇒k+2/k-1 - 3 = 0

⇒k+2/k-1 = 3

Cross multiplying,

⇒k+2 = 3k - 3

⇒k - 3k = -3 + 2

⇒ -2k = -1

⇒ k = 1/2