Question

for what value of k, (x+1) is a factor of p(x)=kx square minus x minus 4

Answer 1

Apply remainder theorem
x+1=0
so ' x = -1

According to remainder theorem p(1) = 0 we get
Plug x = -1 we get
p(1)= k(-1^2) - (-1) -4
0 = k + 1 - 4
0= k - 3
so , k=3

Answer 2

Answer:

k =3

Step-by-step explanation:

x+1 =0

x=-1

pd(x) =-1

p(-1)=k (-1)^2-(-1) -4

o =k+1-4

o =k-3

ans : k =3