Question

For what value of K , x=1, y=3, is the solution of (2k+3)x-(k+1)y-3=0.​

Answer 1

Answer:

K=3

Step-by-step explanation:

x=1 y=3

(2k+3)x-(k+1)y-3=0

(2k+3)×1-(k+1)×3-3 =0

(2k+3)-(3k-3)-3=0

2k+3-3k+3-3=0

2k-3k+3=0

-k+3=0

-k=-3

k=3