For what value of k,x=-2 is a root of k,x²+11x+10=0
YaminiRathi:
I cannot understand the question
once again see it
Answers
Answered by
1
given,
x = -2
kx^2 +11 x +10 =0
k(-2)^2 + 11(-2) + 10 =0
4k - 22 +10 =0
4k = 22-10
4k =12
k = 3
hope it helps
thankyou
x = -2
kx^2 +11 x +10 =0
k(-2)^2 + 11(-2) + 10 =0
4k - 22 +10 =0
4k = 22-10
4k =12
k = 3
hope it helps
thankyou
Answered by
0
Answer:
Step-by-step explanation:
given,
x = -2
kx^2 +11 x +10 =0
k(-2)^2 + 11(-2) + 10 =0
4k - 22 +10 =0
4k = 22-10
4k =12
k = 3
Similar questions