Question

for what value of k, x-3 is a factor of p(x)=x³-6x²+kx-6

Answer 1

put X =3 in the equation and equate it 0 !!
bcz 3 is the root of the polynomial
k= 11

Answer 2

heya here is your answer

x-3=0

x=0+3

x= 3

p(x)= x³-6x²+kx-6 = 0

p(3) = (3)³ - 6* (3)² +k*3 - 6 =0

p(3) = 27 - 6* 9 + 3k -6 =0

= 27+ -54 + 3k + -6 = 0

-33 + 3k = 0

3k= 0+33

3k = 33

k= 33/3

k = 11

hope it helps

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