Question

For what value of k, x = -5 satisfies kx^2 - 3x-k=0?




Please help me to solve this question.​

Answer 1

Answer:

Hola mate

if x=-5

Kx^2-3x-k=0

k-5^2-3×[-5]-k=0

25k+15-k=0

24k +15=0

24k= -15

k = -15/24

k=-5/8

hope it helps.

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Answer 2

Answer:

kx^2-3x-k

putting x = -5

k× (-5)^2 - 3×(-5) - k = 0

25k + 15-k = 0

25k-k = -15

24k = -15

k = -15/24

k= -5/8

hope it will help.........