Math, asked by PARIDHI1704, 9 months ago

For what value of k x =-a is a solution of the equation x² + 2ax-k =0

Answers

Answered by Striker10
4

Step-by-step explanation:

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Answered by johangeo71
2

Answer:

x=-a is a solution of the polynomial.

p(x)= x^{2} +2ax-k

So, p(-a)= a^2-2a^2-k = 0

-a^2-k=0

k=-a^2

Thus, k=-a^2

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