For what value of k x =-a is a solution of the equation x² + 2ax-k =0
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x=-a is a solution of the polynomial.
p(x)= x^{2} +2ax-k
So, p(-a)= a^2-2a^2-k = 0
-a^2-k=0
k=-a^2
Thus, k=-a^2
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