Question

For what value of k , x³-2kx²+16 is divisible by x+2​

Answer 1

Answer:

k=1

Step-by-step explanation:

if x+2 is dividing x^3-2kx^2+16

then remainder will be zero

so let say that polynomial is p(x) then

p(-2)=0

so

(-2)^3-2k(-2)^2+16=0

-8-8k+16=0

-8k+8=0

-8k=-8

k=8/8=1