Question

for what value of ki the equation (k+ 3)x2 - (5-k)
x+ 1 = 0 has
(i)coincident roots (ii) distinct roots ?​

Answer 1

Answer:

i

Step-by-step explanation:

hindi ke sath hai mere sath hi yah khabar bhi i men ek rup yah khabar pata nahi karta to use coment men ek bar to unhone mujhe kaha tum bahut

Answer 2

Step-by-step explanation:

if the given equation has coincident real roots,then they must be equal,

i.e

D=0

b²-4ac=0

{-(5-k)}²-4*(k+3)*1=0

=>25+k²-10k-4k-12=0

=>k²-14k+13=0

=>(k-13)(k-1)=0

so,k=13 or 1

(ii)-if they have distinct roots, then

D>0

b²-4ac>0

k²-14k+13>0

(k-13)(k-1)>0

so, k<1 or k>13

where k€R

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