Question

For what value of kwill the equations 3x + 4y = 1 and (1 − 7k)x − (9k − 2)y − (1 − 2k) = 0 have infinitely many solutions?

Answer 1

Step-by-step explanation:

3x + 4y - 1 = 0

(1-7k)x - (9k-2)y - (1-2k) = 0

given infinity many solution

a1/a2 = b1/b2 = c1/c2

3/1-7k = 4/-9k+2

3(-9k+2) = 4(1-7k)

-27k + 6= 4-28k

k = -2

Answer 2

Answer:

Step-by-step explanation:

3x + 4y - 1 = 0

(1-7k)x - (9k-2)y - (1-2k) = 0

given infinity many solutions

a1/a2 = b1/b2 = c1/c2

3/1-7k = 4/-9k+2

3(-9k+2) = 4(1-7k)

-27k + 6= 4-28k

k = -2