Question

for what value of m, (-4) is a zero of the polynomial x^2 -2 x-(7m+3)

Answer 1

Answer:

$tanA=2−1</p><p></p><p></p><p>tanA=ABBC=12−1</p><p></p><p></p><p> AC2=BA2+BC2=12+(2−1)2=1+2−22+1</p><p></p><p></p><p> AC=4−22</p><p></p><p></p><p> sinA=ACBC=4−222−1cosA=ACAB=4−221</p><p></p><p></p><p> sinA×cosA=4−222−1×4−221=4−222−1</p><p></p><p></p><p> =22(2−1)2−1=221×22=42</p><p></p><p></p><p> cosA×cosAsinA×cosA=42</p><p></p><p></p><p>Multiply numerator & denominator by cosA</p><p></p><p> </p><p></p><p> sec2AtanA=42⇒1+tan2AtanA=42</p><p></p><p></p><p>$

hope it will help u

Answer 2

Answer:

If -4 is zero of given polynomial then

(−4)

2

−2(−4)−(7p+3)=0⇒16+8−7p−3=0⇒7p=21⇒p=3