for what value of m is 2x^3+mx^2+m+3 exactly divisible by ( 2x-1)
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2x-1=o
2x=1
x=1/2
now
2x^3+mx^3+m+3=0
2×(1/2)^3+m(1/2)^+m+3=0
2×1/4×3+m×1/4+m+3=0
3/2+m/4+m+3=0
6+m+4m+12/4=0
5m+18/4=4
5m+18=16
5m=16-18
5m=-2
m=-2/5
Hope it help
2x=1
x=1/2
now
2x^3+mx^3+m+3=0
2×(1/2)^3+m(1/2)^+m+3=0
2×1/4×3+m×1/4+m+3=0
3/2+m/4+m+3=0
6+m+4m+12/4=0
5m+18/4=4
5m+18=16
5m=16-18
5m=-2
m=-2/5
Hope it help
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