Question

For what value of m is [/tex][tex](x^3-2mx^2+ 16) divisible by (x+2)?

Answer 1

Answer:

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Answer 2

Answer:

m = 1

${x}^{3} - 2m {x}^{2} + 16 = ( { - 2}^{3} - 2 \times m \times { - 2}^{2} + 16 = - 8 + ( - 8m )+ 16 = - 8m + 8 = 8 = 8m = m = 1$

Step-by-step explanation:

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