Math, asked by premaskumarprema, 9 months ago

For what value of m is the polynomial x cube +2mx square+16 divisible by x+2

Answers

Answered by pranavgreat169
3

Answer:

-1

Step-by-step explanation:

p(x) = x^3 + 2mx^2 +16

since it is divisible by x+2 therefore p(-2) = 0 {factor theorem}

p(-2) = (-2)^3 + 2m(-2)^2+16

-8+8m+16=0

8m =-8

m = -1

Answered by 12adhish
0

Answer:

-1

Step-by-step explanation:

p(x) = x^3 + 2mx^2 +16

since it is divisible by x+2 therefore p(-2) = 0 {factor theorem}

p(-2) = (-2)^3 + 2m(-2)^2+16

-8+8m+16=0

8m =-8

m = -1

Step-by-step explanation:

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