For what value of m is the polynomial x cube +2mx square+16 divisible by x+2
Answers
Answered by
3
Answer:
-1
Step-by-step explanation:
p(x) = x^3 + 2mx^2 +16
since it is divisible by x+2 therefore p(-2) = 0 {factor theorem}
p(-2) = (-2)^3 + 2m(-2)^2+16
-8+8m+16=0
8m =-8
m = -1
Answered by
0
Answer:
-1
Step-by-step explanation:
p(x) = x^3 + 2mx^2 +16
since it is divisible by x+2 therefore p(-2) = 0 {factor theorem}
p(-2) = (-2)^3 + 2m(-2)^2+16
-8+8m+16=0
8m =-8
m = -1
Step-by-step explanation:
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