for what value of m is the polynomial x³-2mx²+16 divisible by (x+2)
plz help
anujtanwar:
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Answers
Answered by
1
given:
x+2 (now here we will form an eq.)
x+2=0
x= -2
now we will put the value of x
(-2)^3 -2m(-2)^2 +16
-2 +8m+16 (new eq will be formed)
-2 +8m +16=0
8m= -16 +2 on transposing
m=-14/8
m= -7/4
x+2 (now here we will form an eq.)
x+2=0
x= -2
now we will put the value of x
(-2)^3 -2m(-2)^2 +16
-2 +8m+16 (new eq will be formed)
-2 +8m +16=0
8m= -16 +2 on transposing
m=-14/8
m= -7/4
Answered by
1
(- 2)^3- 2m(-2)^2+16=0 gives m=1
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