Math, asked by amitmal2571, 1 year ago

For what value of m is x^3- 2mn^2+16 divisible by x+27

Answers

Answered by komalbhambri2004
1

Answer:

Step-by-step explanation:

p(x)=x^3-2mx^2+16

x+27

to make p(x) divisible by x+27

p(x)=0

also putting value of x in p(x)

x+27=0

x= -27

(-27)^3-2m(-27)^2+16=0

-19683-2m(729)+16=0

-1458m= -16+19683

-1458m=19667

m= -19667/1458

m= -13.48

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