for what value of m is x^3 -2mx^2 +16 divisible by x+2
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Answered by
15
keep x=-2 in the equation so -8-2m(-2^2)+16=0 so m=1 please mark it as brainliest
Answered by
13
here,
x=-2
-2^3-2m-2^2+16 = 0
-8m=-8
m=1
x=-2
-2^3-2m-2^2+16 = 0
-8m=-8
m=1
praneethks:
please check the question properly dude
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