for what value of m is x cube -2mx square+16 divisible by x+2
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Answer:
Step-by-step explanation:
p(x)=x^3-2mx^2+16
x+2
putting value of x in p(x)
x+2=0
x= -2
also as p(x) is divisible by x+2
therefore,
p(x)=0
thus,
(-2)^3-2m(-2)^2+16=0
(-8)-2m(4)+16=0
-8m= -16+8
-8m= -8
8m=8
m=1
therefore,value of m=1
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