Math, asked by thisissharma, 1 year ago

for what value of m is x cube -2mx square+16 divisible by x+2

Answers

Answered by komalbhambri2004
0

Answer:

Step-by-step explanation:

p(x)=x^3-2mx^2+16

x+2

putting value of x in p(x)

x+2=0

x= -2

also as p(x) is divisible by x+2

therefore,

p(x)=0

thus,

(-2)^3-2m(-2)^2+16=0

(-8)-2m(4)+16=0

-8m= -16+8

-8m= -8

8m=8

m=1

therefore,value of m=1

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