Question

For what value of m is x³-2 mx²+16 divisible by x+2 ​

Answer 1

Answer:

1

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Answer 2

Step-by-step explanation:

x^3-2mx^2+16÷x+2

x+2=0

x=-2

p(x) =x^3-2mx^2+16

p(-2)=(-2)^3-2m(-2)^2+16

=-8-2m(4)+16=0

= -8-8m+16=0

=8-8m=0

=-8m=0-8

= -8m=-8

=m = -8/-8

=m=1