for what value of m is x3-2mx2+16 divisible by x+2
Answers
Answered by
12
Question:
For what value of m is x^3 - 2mx^2 + 16 divisible by x+2.
To Find:
- Value of m.
Solution:
Let,
p(x) = x^3 - 2mx^2 = 16
Since,
is divisible by , then remainder
-2^3 - 2m - 2^2 + 16 = 0
Hence,
The value of m is 1.
Answered by
20
Answer:
m=1
Step-by-step explanation:
f (-2) = (-2)^3-2(m)(-2)^2+16=0
= -8 - 8m+16=0
= 8- 8m=0
8=8m
1=m
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