Math, asked by riyanshr97, 8 months ago

for what value of m is x3-2mx2+16 divisible by x+2​

Answers

Answered by Uriyella
12

Question:

For what value of m is x^3 - 2mx^2 + 16 divisible by x+2.

To Find:

  • Value of m.

Solution:

Let,

p(x) = x^3  - 2mx^2 = 16

Since,

 p(x) is divisible by  (x + 2) , then remainder  = 0

 P(-2) = 0

-2^3 - 2m - 2^2 + 16 = 0

 \implies-8 - 8m + 16 = 0

 \implies8 = 8m

 \huge \boxed {m = 1}

Hence,

The value of m is 1.

Answered by Mounika200525
20

Answer:

m=1

Step-by-step explanation:

f (-2) = (-2)^3-2(m)(-2)^2+16=0

= -8 - 8m+16=0

= 8- 8m=0

8=8m

1=m

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