Question

for what value of m is x3-2mx2+16 divisible by x+2 ?

Answer 1

Answer:

The value of m is 1.

Step-by-step explanation:

$\text{Given the polynomial }x^3-2mx^2+16$

$\text{ we have to find the value of m for which given polynomial is divisible by} x+2$

$P(x)=x^3-2mx^2+16$

when the above polynomial is divisible is x+2 then the remainder will be 0.

By remainder theorem

$P(-2)=0$

$(-2)^3-2m(-2)^2+16=0$

$-8-8m+16=0$

$8m=8$

Divide throughout the equation by 8

$m=\frac{8}{8}=1$

Hence, the value of m is 1.

Answer 2

m=1 thanks for seen answer