For what value of *m* is x³ - 2mx²+16 divisible by x+2
Answers
Answered by
16
Answer:
x³ - 2mx²+16
x+2
x= -2
x³ - 2mx²+16
(-2)³ - 2 m (-2)² + 16=0
-8 - 8m + 16=0
-8m + 8 =0
-8m = -8
8m = 8
m = 8/8
m= 1
the value of m is 1
Answered by
4
Answer:
1
Step-by-step explanation:
p(x) = x³-2mx² +16
substitute -2 in place of x
0= -2³-2m(-2)² +16 [According to factor theorem]
= 0= -8 +8m +16
= 0= 8+8m
= 8=8m
= m= 8/8
= m=1
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