Math, asked by sabihawali02, 1 month ago

For what value of *m* is x³ - 2mx²+16 divisible by x+2​

Answers

Answered by bhoomimaurya2302
16

Answer:

x³ - 2mx²+16

x+2

x= -2

x³ - 2mx²+16

(-2)³ - 2 m (-2)² + 16=0

-8 - 8m + 16=0

-8m + 8 =0

-8m = -8

8m = 8

m = 8/8

m= 1

the value of m is 1

Answered by atharvjoshi3
4

Answer:

1

Step-by-step explanation:

p(x) = x³-2mx² +16

substitute -2 in place of x

0= -2³-2m(-2)² +16 [According to factor theorem]

= 0= -8 +8m +16

= 0= 8+8m

= 8=8m

= m= 8/8

= m=1

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