Question

For what value of m is (x³-2mx²+16) divisible by x+2​

Answer 1

Here is your answer Hope it helps you .

Answer 2

Answer:

$\sf \: Let \: p(x) = x ^{3} -2m {x}^{2} +16 \\ \sf \: Since, \: p(x) \: is \: divisible \: by \: (x+2), \: then \: remainder = 0 \\ \sf \: P(-2) \: = 0 \\ \sf \: ⇒ (-2) ^{3} -2m(-2)^{2} + 16=0 \\ \sf⇒ -8-8m+16=0 \\ \sf⇒ 8 = 8 m \\ \sf \: m = 1 \\ \sf \: Hence, \: the \: value \: of \: m \: is \: 1 .$