for what value of m the quadratic equation X square - 4 x + m is equal to zero will have a real and equal roots
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Answered by
4
Hey
Here is your answer,
X^2 - 4x + m = 0
a = 1
b = -4
c = m
b^2 - 4ac = 0
(-4)^2 - 4 x 1 x m = 0
16 - 4m = 0
-4m = -16
m = -16/-4
m = 4
Hope it helps you!
Here is your answer,
X^2 - 4x + m = 0
a = 1
b = -4
c = m
b^2 - 4ac = 0
(-4)^2 - 4 x 1 x m = 0
16 - 4m = 0
-4m = -16
m = -16/-4
m = 4
Hope it helps you!
Answered by
2
For real and equal roots, D (discriminant) = 0
we know that D = b^2 - 4ac..
Later steps are in the attached picture
we know that D = b^2 - 4ac..
Later steps are in the attached picture
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ketulrmadrid20pbfeg5:
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