Question

for what value of m the sum of the roots of mx^2 + 6x + 4m = 0 be equal to the product of the roots

Answer 1

heya it's Aastha...
on comparing equation with standard form...

a = m , b= 6 ,c = 4m

◆D = b2 -4ac

◆D = 36 - 16m^2

◆0 = 36 - 16 m^2

◆16 m^2 = 36

◆m^2 = 9/4

m = 3/2 .
◆
Hope it help you...

Answer 2

Let p (x) = mx^2 + 6x + 4m=0
So,
By comparing with the form
ax^2 + bx + c = 0
a=m , b=6 & c = 4m
Now,
Sum of roots = -b / a
= -6 / m

Product of the roots = c / a = 4m/m
= 4

Now,
Sum of the roots = product of the roots
Therefore,
-6/m = 4
m = -6/4
m = -3/2.