Question

For what value of m ,the vecto A = 2 i^ +3 j^ - 6 k^ is perpendicular to vector B= 3 i^ - m j^ + 6 k^. *

3 points

m=-10

m=18

m-12

m=15

​

Answer 1

Answer:

For A to be perpendicular to B, A.B should be zero

A.B=(2i + 3j- 6k).(3i-xj+6k)=0

6-3M-36=0

-30-3M=0

3M=-30

or M=-10

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