Question

For what value of (m) , the vector 4i+2j-3k AND mi-j+√3k have same magnitude.

Answer 1

Answer:

m = 5

Explanation:

same magnitude

\begin{lgathered}\sqrt{ {4}^{2} + {2}^{2} + {3}^{2} } = \sqrt{ {m}^{2} + {1}^{2} + { \sqrt{3} }^{2} } \\ \sqrt{16 + 4 + 9} = \sqrt{ {m}^{2} + 1 + 3} \\ both \: side \: square \\ 29 = {m}^{2} + 4 \\ 29 - 4 = {m}^{2} \\ \sqrt{25} = m \\ m = 5\end{lgathered}

m=5