Physics, asked by himanshuparmar0573, 7 months ago

-For what value of m ,the vector A = 2 i^ +3 j^ - 6 k^ is perpendicular to vector B= 3 i^ - m j^ + 6 k^​

Answers

Answered by Itzraisingstar
10

Answer:

Explanation:

For A to be perpendicular to B, A.B should be zero .

A.B=(2i + 3j- 6k).(3i-xj+6k)=0 ,

6-3M-36=0 ,

-30-3M=0 ,

3M=-30 ,

or M=-10 .

Hope it helps you

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Answered by divyanshsiit
2
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