Question

For what value of m the vector a is 2i^+3j^+6k^ is perpendicular to vector b 3i^-mj^+6k^​

Answer 1

Answer:For A to be perpendicular to B, A.B should be zero

A.B=(2i + 3j- 6k).(3i-xj+6k)=0

6-3M-36=0

-30-3M=0

3M=-30

or M=-10

Answer 2

Explanation:

vectors are perpendicular

→ There dot product is 0

→ (2×3) + (-m ×3) + (6×6)= 0

→ 42 = 3m

→ m = 14