Question

For what value of m x3 -2mx2 +16 is divisible by x+2 ?
Correct answer will be marked brainliest

Answer 1

Answer:

X+2=0

so x=-2

x³-2mx²+16=0

substituting -2 in the place of x

(-2)³-2m(-2)²+16=0

-8-8m+16=0

8-8m=0

-8m=-8

m=8÷8=1  (both the negative signs are cancelled out)

therefore the value of m is 1