Question

for what value of n 1 are the nth terms of two AP 1,7 13 19 .......and 100 95,90........ equal​

Answer 1

Answer:

=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=

10th Term Of Both The AP's Are Equal

=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=

Step-by-step explanation:

=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=

See The Attachment My Friend....

=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=

Answer 2

Answer:

For the 1st series, a= 1, d= 6

Hence, an = 1+(n-1).6 = 6n-5

For the 2nd series, a= 100, d= -5

Hence, an= 100+(n-1)(-5) = 105-5n

ATQ, 6n-5 = 105-5n

=> n= 10

Hence, 10 term of the AP are same.