Question

For what value of n
(10^n-1) (10^n +1) = 999999999999​

Answer 1

Answer:

Step-by-step explanation:

THEREFORE, if n is even, n(n + 2) is always a multiple of 8. n(n+1)(n+2) is the product of three consecutive integers because n is an integer. In any set of three consecutive numbers, there must be at least one odd and one even. The product of three or more consecutive integers will always be EVEN