Question

for what value of n and nth term of the AP:74,77,80,...and 3,10,17,....equal
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Answer 1

Step-by-step explanation:

63,65,67.......

a=63,d=2

nth term =a+(n+1)d

=63+(n+1)2

=61+2n

(b)

3,10,17....

a=3,d=7

nth term =a+(n−1)d

=3+(n−1)7

=−4+7n

Now nth

terms of 2 ap’s as equal

So 61+2n=7n−4

⇒5n=65

⇒n=13

13th term of A.p.s are equal

Answer 2

Answer:

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Step-by-step explanation:

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