for what value of n , are nth terms of two ap`s :2,5,8... and 117,111,105..... equal
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a= 2, d= 5-2 =3, n=n
an = a+ (n-1)d=2+(n-1)3 = 2+3n-3=3n-1
therefore the nth term of A. P. is 3n-1.
a= 117 , d= 111-117= -6, n=n
an=a+ (n-1)d
an= 117+ (n-1)-6
an= 117-6n+6
an= -6n +123
therefore the nth term of A. P. is-6n +123
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