For what value of n are the n th term of two AP:63,65,67….... and 3,10,17....... equal
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Answered by
0
you have to put value equally like:-
an=a+(n-1)d = a'n =a+(n-1)d
here you can put values
Answered by
1
in first AP a=63,d=2 nth term=63+(n-1)2=63+2n-2=2n+61 in second AP a=3,d=7 nth term=3+(n-1)7=3+7n-7=7n-4 7n-4=2n+61 5n=65 n=65/5=13 thus, n=13
Plz hit the heart
sangeeth10:
how 61 come in the equation?
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