for what value of n are the nth term af the two APs are 53,55,57,and4,11,18 are equal
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we know ,
Tn = a+(n-1) d
where a is first term and d is the common difference of AP
now,
for first series ----
Tn=53 + ( n-1) 2
for second series ------
T"n = 4 + (n- 1) 7
a/c to question ,
T"n = Tn
4 + (n-1) 7 = 53 +(n-1) 2
5 (n - 1) = 53 - 4
5 (n- 1)= 49
n-1 = 9.8
n= 10.8
but we know value of doesn't exist in fraction .
so, n=11 ( approx )
Tn = a+(n-1) d
where a is first term and d is the common difference of AP
now,
for first series ----
Tn=53 + ( n-1) 2
for second series ------
T"n = 4 + (n- 1) 7
a/c to question ,
T"n = Tn
4 + (n-1) 7 = 53 +(n-1) 2
5 (n - 1) = 53 - 4
5 (n- 1)= 49
n-1 = 9.8
n= 10.8
but we know value of doesn't exist in fraction .
so, n=11 ( approx )
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