Question

for what value of n, are the nth term of
APs : 63 ,65, 67,......... and 3, 10, 17, ........equals?​

Answer 1

Answer:

63,65,67.......

a=63,d=2

n

th

term =a+(n+1)d

=63+(n+1)2

=61+2n

(b)

3,10,17....

a=3,d=7

n

th

term =a+(n−1)d

=3+(n−1)7

=−4+7n

Now n

th

terms of 2 ap’s as equal

So 61+2n=7n−4

⇒5n=65

⇒n=13

13

th

term of A.p.s are equal

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