For what value of n are the nth term of the following two ap are same 13,19,25 and 69,68,67
Answers
Let the nth terms of the given progressions be and respectively.
▶ The first AP is 13, 19, 25...... .
Let its first term be a and common difference be d. Then,
=> a = 13 and D = ( 19 - 13 ) = 6.
So, its nth term is given by
= a + ( n - 1 )d.
=> = 13 + ( n - 1 ) × 6.
=> = 13 + 6n - 6.
=> = 6n + 7........(1).
▶ The second AP is 69, 68, 67..... .
Let its first term be A and common difference be D. Then,
=> A = 69 and D = ( 68 - 69 ) = -1.
So , its nth term is given by
= A + ( n - 1 )D.
=> = 69 + ( n - 1 ) × (-1).
=> = 69 - n + 1.
=> = 70 - n..........(2).
▶ Now,
A/Q,
=> = .
=> 6n + 7 = 70 - n.
=> 6n + n = 70 - 7.
=> 7n = 63.
=> n =
✔✔ Hence, it is solved ✅✅.
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HEY THERE!!
Let to First Arithmetic Progression tn and Tn Is second Arithmetic Progression (AP):-
First Arithmetic Progression:- 13,19,25......
Here,
a=13
d=19-13
= 6
According to the Formula of Arithmetic Progression:- Tn=a+(n-1)d
Now, Substitute the value of first term and CommOn Difference on Given Arithmetic Progression;-
=> Tn=a+(n-1)d
=> Tn=13+(n-1)6
=> Tn=13+6n-6
=> Tn=7+6n
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Second Arithmetic Progression:- 69,68,67.....
Here,
a=69
d=68-69
= -1
According to the Formula of Arithmetic Progression:- Tn=a+(n-1)d
Now, Substitute the value of first term and CommOn Difference on Given Arithmetic Progression;-
tn=a+(n-1)d
=> tn=69+(n-1)-1
=> tn=69-n+
=> tn=69+1-n
=> tn=70-n
Considering on Question;-
Both Arithmetic Progression( AP) are in same terms:-
Then,
Tn=tn
=> 7+6n=70-n
=> 7-70=-n-6n
=> -63=-7n
=> 63=7n
=> n=63/7
=> n= 9
Hence, For value of n(9) are the nth term of the following two ap are same 13,19,25 and 69,68,67
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