Math, asked by parulranyal5058, 1 year ago

For what value of n are the nth term of the following two ap are same 13,19,25 and 69,68,67

Answers

Answered by Anonymous
183
Hey there !!

Let the nth terms of the given progressions be  t \tiny{n}  and    T  \tiny{n}   respectively.

▶ The first AP is 13, 19, 25...... .

Let its first term be a and common difference be d. Then,

=> a = 13 and D = ( 19 - 13 ) = 6.

So, its nth term is given by

 t \tiny{n}  = a + ( n - 1 )d.

=>  t \tiny{n}   = 13 + ( n - 1 ) × 6.

=>   t \tiny{n} = 13 + 6n - 6.

=>  t \tiny{n}  = 6n + 7........(1).

▶ The second AP is 69, 68, 67..... .

Let its first term be A and common difference be D. Then,

=> A = 69 and D = ( 68 - 69 ) = -1.

So , its nth term is given by

 T \tiny{n}  = A + ( n - 1 )D.

=>  T \tiny{n} = 69 + ( n - 1 ) × (-1).

=>  T \tiny{n}  = 69 - n + 1.

=>  T \tiny{n}  = 70 - n..........(2).

▶ Now,

A/Q,

=>  t \tiny{n}  =  T \tiny{n}  .

=> 6n + 7 = 70 - n.

=> 6n + n = 70 - 7.

=> 7n = 63.

=> n =  \frac{63}{7} .

 \huge \boxed{ \boxed{ \bf => n = 9. }}

✔✔ Hence, it is solved ✅✅.

____________________________________


 \huge \boxed{ \mathbb{THANKS}}  


 \huge \bf{ \#BeBrainly. }
Answered by Anonymous
54

HEY THERE!!



Let to First Arithmetic Progression tn and Tn Is second Arithmetic Progression (AP):-



First Arithmetic Progression:- 13,19,25......



Here,


a=13



d=19-13


  = 6



According to the Formula of Arithmetic Progression:- Tn=a+(n-1)d




Now, Substitute the value of first term and CommOn Difference on  Given Arithmetic Progression;-



=> Tn=a+(n-1)d



=> Tn=13+(n-1)6



=> Tn=13+6n-6



=> Tn=7+6n



==================================



Second Arithmetic Progression:- 69,68,67.....



Here,


a=69



d=68-69


  = -1



According to the Formula of Arithmetic Progression:- Tn=a+(n-1)d




Now, Substitute the value of first term and CommOn Difference on  Given Arithmetic Progression;-



tn=a+(n-1)d



=> tn=69+(n-1)-1



=> tn=69-n+



=> tn=69+1-n



=> tn=70-n




Considering on Question;-



Both Arithmetic Progression( AP) are in same terms:-



Then,



Tn=tn



=> 7+6n=70-n



=> 7-70=-n-6n



=> -63=-7n



=> 63=7n



=> n=63/7



=> n= 9





Hence, For value of n(9) are the nth term of the following two ap are same 13,19,25 and 69,68,67



======================================






LEGENDARYSUMIT01: help me plz
Anonymous: Ya
LEGENDARYSUMIT01: i m giving the question answer with process
Anonymous: yes
Anonymous: post again
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