Question

For what value of n are the nth terms of aps:63,65,67......and3,10,17....equal?

Answer 1

1st ka hai 69
2nd ka hai 24 answer...

Easy question. ...

Answer 2

For First AP = 63, 65, 67 …..

Here

a = 63

d = 2

$\bf\huge a_{n} = a + (n - 1)d$  

$\bf\huge a_{n} = 63 + (n - 1)2$

= 63 + 2n - 2

= 61 + 2n …. (1)

For Second AP = 3, 10, 17 …..

Here

a = 2

d = 7

$\bf\huge a_{n} = a + (n - 1)d$  

$\bf\huge a_{n} = 3 + (n - 1)7$

= 3 + 7n - 7

= 7n - 4 …. (2)

From (1) and (2) we get :-

61 + 2n = 7n - 4

5n = 65

$\bf\huge n = \frac{65}{5}$

n = 13

Therefore  

nth term is 13