Math, asked by Harshrajesh2917, 1 year ago

For what value of n are the nth terms of two


a.p.`s is 63,65,67,and 3,10,17equal

Answers

Answered by saurabhsinghbihari
6
i hope this answer would be helpful for you
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Answered by sanya55
3
Heya!!Here is your answer friend ⤵⤵

AP 1. 63, 65 , 67

Here A= 63 and D= 2


An= A+ (n-1) D

An1= 63 + (n-1)2 --------(1)


AP2. 3,10,17

Here A=3 and D= 7

An2. = 3 + (n-1) 7........(2)

Putting equation (1) and (2) equal . We have,


63+ 2n -2 = 3 + 7n -7

2n-7n = -7+3 -61

-5n= -65

n= 65/5

n= 13


Hence the required value of N for which the n th terms of the two given APs are equal is 13.


Hope it helps you ✌✌
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