For what value of n are the nth terms of two
a.p.`s is 63,65,67,and 3,10,17equal
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Heya!!Here is your answer friend ⤵⤵
AP 1. 63, 65 , 67
Here A= 63 and D= 2
An= A+ (n-1) D
An1= 63 + (n-1)2 --------(1)
AP2. 3,10,17
Here A=3 and D= 7
An2. = 3 + (n-1) 7........(2)
Putting equation (1) and (2) equal . We have,
63+ 2n -2 = 3 + 7n -7
2n-7n = -7+3 -61
-5n= -65
n= 65/5
n= 13
Hence the required value of N for which the n th terms of the two given APs are equal is 13.
Hope it helps you ✌✌
AP 1. 63, 65 , 67
Here A= 63 and D= 2
An= A+ (n-1) D
An1= 63 + (n-1)2 --------(1)
AP2. 3,10,17
Here A=3 and D= 7
An2. = 3 + (n-1) 7........(2)
Putting equation (1) and (2) equal . We have,
63+ 2n -2 = 3 + 7n -7
2n-7n = -7+3 -61
-5n= -65
n= 65/5
n= 13
Hence the required value of N for which the n th terms of the two given APs are equal is 13.
Hope it helps you ✌✌
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