Question

For what value of n, are the nth terms of two AP's : 63,65,67,and3, 7,17

Answer 1

Answer:

3 and 8

Step-by-step explanation:

$a = 63 \: and \: 3$

$d = 2$

$l = 67 \: and \: 17$

so,

$n = ( \frac{l - a}{d}) + 1$

$= (\frac{67 - 63}{2}) + 1$

$= ( \frac{4}{2} ) + 1$

$= 2 + 1$

$n = 3$

this is for the first AP

now we will find for the second AP

$n = (\frac{17 - 3}{2} ) + 1$

$n = 8$