Question

For what value of n , are the nth terms of two ap63,65,77.....and 3,10,13...equal?

Answer 1

I think your question is wrong
I think this is the right question

ap: 63,65,67---
ap: 3,10,17---

your answer is here✌✌✌✌✌✌

A.P.:63,65,67---
a=63 d= a2-a1
=65-63
=2
an=a+(n-1)d
an=63+(n-1)×2
an=63+2n-2
an=61+2n

second, A.P.:3,10,17---
a=3 d=a2-a1
=10-3
=7

tn=a+(n-1)d
tn=3+(n-1)×7
tn=3+7n-7
tn=7n+4

according to question,
an=tn
=>61+2n
=>2n-7n= -4-61
=>-5n= -65
=> n= -65/5
=> n=13

hence, 13th term of two ap are equal.
hope it helps you
✌✌✌✌✌✌✌✌✌✌
palak shrivastava