Question

For what value of n are the nth terms of two APs 63,65,67,... and 3,10,17,.. are equal?​

Answer 1

Step-by-step explanation:

63,65,67,..... is an AP.... given

here a=63 and d = 2

tn = a + (n-1)d..... formula for nth term

tn= 63+(n-1)2

tn=63+2n-2

tn= 61+2n

3,10,17 ,... is an AP ... given

here a=3 and d=7

tn = a+(n-1)d

tn= 3+(n-1)7

tn=3+7n-7

tn=-4+7n

since the nth tern of both the APs are equal

61+2n=-4+7n

61+4=7n-2n

65=5n

n=65/5

n=13

t13=3+(13-1)7

t13=3+12×7

t13=3+84

t13=87

The 13th term of both the AP are equal and its value is 87

PLEASE MARK AS BRAILIEST