Question

For what value of n, are the nth terms of two APs:63, 65, 67,. . . and 3, 10, 17, . . . equal

Answer 1

Let the 1st AP be A =63,65,68.....


Let the 2nd AP be B = 3,7,17......
For A , common difference is : 65-63 = 2
For B ,common difference is : 10-3 = 7

Now Let the nth term be An and Bn respectively.
According to question
An = Bn
=> 63+(n-1)2 = 3+(n-1)7
=>60 + 2n-2 = 7n-7
=>65 = 5n
=> n = 13
Thus 13th term of both AP's will be same

Answer 2

Answer:

Step-by-step explanation:

Let the 1st AP be A =63,65,68.....

Let the 2nd AP be B = 3,7,17......

For A , common difference is : 65-63 = 2

For B ,common difference is : 10-3 = 7

Now Let the nth term be An and Bn respectively.

According to question

An = Bn

=> 63+(n-1)2 = 3+(n-1)7

=>60 + 2n-2 = 7n-7

=>65 = 5n

=> n = 13

Thus 13th term of both AP's will be same