for what value of n are the nth terms of two APs : 63, 65, 67,... and 3, 10, 17,... equal?
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Answered by
6
The value of n must be 13. As in 63,65,67,... the eqn is :63+(n-1)2;
and for 3,10,17,.... the eqn is:3+(n-1)7;
then solve them .
and for 3,10,17,.... the eqn is:3+(n-1)7;
then solve them .
Answered by
33
n=13............ hope this helps you.....
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kash1411:
really helped! thanks
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