for what value of n are the nth terms of two APs: 63,65,67,....and 3,10,17,....equal?
Answers
Answered by
2
Answer:
13th term
Step-by-step explanation:
63,65,67.......
a=63,d=2
n
th
term =a+(n+1)d
=63+(n+1)2
=61+2n
(b)
3,10,17....
a=3,d=7
n
th
term =a+(n−1)d
=3+(n−1)7
=−4+7n
Now n
th
terms of 2 ap’s as equal
So 61+2n=7n−4
⇒5n=65
⇒n=13
13
th
term of A.p.s are equal
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Answered by
3
Answer:
hii mate
Step-by-step explanation:
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