For what value of n are the nth terms of two APs:63,65,67....and 3,10,17.....equal?
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23
hey mate...
here is ur answer..
in first AP a=63,d=2 nth term=63+(n-1)2=63+2n-2=2n+61 in second APa=3,d=7 nth term=3+(n-1)7=3+7n-7=7n-4 7n-4=2n+61 5n=65n=65/5=13 thus, n=13
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here is ur answer..
in first AP a=63,d=2 nth term=63+(n-1)2=63+2n-2=2n+61 in second APa=3,d=7 nth term=3+(n-1)7=3+7n-7=7n-4 7n-4=2n+61 5n=65n=65/5=13 thus, n=13
I hope it's help u
mark it as brainlesit
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hey dear friend
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