For what value of n are the nth terms of two APs 63, 65, 67, ....amd 3, 10, 17, ...... are equal.
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in first AP a=63,d=2 nth term=63+(n-1)2=63+2n-2=2n+61 in second AP a=3,d=7 nth term=3+(n-1)7=3+7n-7=7n-4 7n-4=2n+61 5n=65 n=65/5=13thus, n=13
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here is your answer
in first AP a=63,d=2 nth term=63+(n-1)2=63+2n-2=2n+61 in second AP a=3,d=7 nth term=3+(n-1)7=3+7n-7=7n-4 7n-4=2n+61 5n=65 n=65/5=13thus, n=13
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