Math, asked by Faisal4r, 4 months ago

For what value of n is the graph of Kn Eulerian ?​

Answers

Answered by UniqueBabe
6

Kn has an Eulerian trail (or an open Eulerian trail) if there exists exactly two vertices of odd degree. Since each of the n vertices has degree n − 1, we need n = 2.

Answered by VaibhavSR
3

Answer: n=2

Step-by-step explanation:

  • For the graph of Kn to be Eulerian there must be two vertices of odd degree.
  • So the value of n will always be (n-1).
  • The minimum value of n will be 2.
  • Hence,value of n will be 2 for the graph to be Eulerian.

#SPJ3

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